LeetCode 3047: Find the Largest Area of Square Inside Two Rectangles Solution
Master LeetCode problem 3047 (Find the Largest Area of Square Inside Two Rectangles), a medium challenge, with our optimized solutions in Java, C++, and Python. Explore detailed explanations, test your code in our interactive editor, and prepare for coding interviews.
Problem Explanation
Explanation
To find the largest area of a square inside the intersecting region of at least two rectangles, we can iterate through all pairs of rectangles and find the intersection of their regions. For each pair of rectangles, we calculate the side length of the largest square that can fit inside their intersection. We keep track of the maximum area found so far and return it as the result. If no square can fit inside the intersection of any two rectangles, we return 0.
Algorithm:
- Iterate through all pairs of rectangles.
- Find the intersection of the two rectangles.
- Calculate the side length of the largest square that can fit inside the intersection.
- Update the maximum area found so far.
- Return the maximum area as the result.
Time Complexity: O(n^2) where n is the number of rectangles Space Complexity: O(1)
Solution Code
class Solution {
public int largestArea(int[][] bottomLeft, int[][] topRight) {
int maxArea = 0;
for (int i = 0; i < bottomLeft.length; i++) {
for (int j = i + 1; j < bottomLeft.length; j++) {
int x1 = Math.max(bottomLeft[i][0], bottomLeft[j][0]);
int y1 = Math.max(bottomLeft[i][1], bottomLeft[j][1]);
int x2 = Math.min(topRight[i][0], topRight[j][0]);
int y2 = Math.min(topRight[i][1], topRight[j][1]);
if (x1 < x2 && y1 < y2) {
int side = Math.min(x2 - x1, y2 - y1);
maxArea = Math.max(maxArea, side * side);
}
}
}
return maxArea;
}
}Try It Yourself
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