LeetCode 3050: Pizza Toppings Cost Analysis Solution
Master LeetCode problem 3050 (Pizza Toppings Cost Analysis), a medium challenge, with our optimized solutions in Java, C++, and Python. Explore detailed explanations, test your code in our interactive editor, and prepare for coding interviews.
3050. Pizza Toppings Cost Analysis
Problem Explanation
Explanation:
To solve this problem, we can iterate through every possible combination of toppings and calculate the cost of each combination. We will maintain a list to store the cost of each combination sorted in descending order. Finally, we will return the top k costs from the list.
Algorithm:
- Iterate through all possible combinations of toppings using recursion.
- Keep track of the cost of each combination.
- Store the cost of each combination in a list.
- Sort the list of costs in descending order.
- Return the top
kcosts from the list.
Time Complexity:
The time complexity of this algorithm is O(2^N) where N is the number of toppings.
Space Complexity:
The space complexity of this algorithm is O(N) where N is the number of toppings.
:
Solution Code
import java.util.*;
class Solution {
public List<Integer> pizzaToppingsCost(int[] toppingsCost, int k) {
List<Integer> result = new ArrayList<>();
backtrack(toppingsCost, 0, k, 0, result);
Collections.sort(result, Collections.reverseOrder());
return result.subList(0, k);
}
private void backtrack(int[] toppingsCost, int index, int k, int currentCost, List<Integer> result) {
if (index == toppingsCost.length) {
result.add(currentCost);
return;
}
for (int i = 0; i <= k; i++) {
backtrack(toppingsCost, index + 1, k, currentCost + i * toppingsCost[index], result);
}
}
}Try It Yourself
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