LeetCode 3073: Maximum Increasing Triplet Value Solution

Master LeetCode problem 3073 (Maximum Increasing Triplet Value), a medium challenge, with our optimized solutions in Java, C++, and Python. Explore detailed explanations, test your code in our interactive editor, and prepare for coding interviews.

3073. Maximum Increasing Triplet Value

Medium

Array Ordered Set

Problem Explanation

Explanation

To solve this problem, we need to find if there exists a triplet of numbers in the given array such that it forms an increasing subsequence. We can achieve this by iterating through the array and maintaining two variables first and second to keep track of the minimum and second minimum values seen so far. If we encounter a number greater than second, we have found a triplet that satisfies the condition.

Algorithm

Initialize first and second to positive infinity.
Iterate through the array.
If the current element is less than first, update first to the current element.
Else if the current element is less than second, update second to the current element.
Else, return true as we have found a triplet.
If no triplet is found during the iteration, return false.

Time Complexity

The time complexity of this algorithm is O(n), where n is the number of elements in the array.

Space Complexity

The space complexity of this algorithm is O(1), as we are using only a constant amount of extra space.

Solution Code

class Solution {
    public boolean increasingTriplet(int[] nums) {
        int first = Integer.MAX_VALUE;
        int second = Integer.MAX_VALUE;
        
        for (int num : nums) {
            if (num <= first) {
                first = num;
            } else if (num <= second) {
                second = num;
            } else {
                return true;
            }
        }
        
        return false;
    }
}

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