LeetCode 3079: Find the Sum of Encrypted Integers Solution

Master LeetCode problem 3079 (Find the Sum of Encrypted Integers), a easy challenge, with our optimized solutions in Java, C++, and Python. Explore detailed explanations, test your code in our interactive editor, and prepare for coding interviews.

3079. Find the Sum of Encrypted Integers

Easy

Array Math

Problem Explanation

Explanation:

To solve this problem, we need to iterate through the given array of integers, find the largest digit in each number, and then replace all digits with this largest digit. Finally, we sum up all the encrypted numbers and return the result.

Algorithm:

Initialize a variable result to store the sum of encrypted integers.
Iterate through each number in the input array.
For each number, find the largest digit by converting the number to a string, finding the maximum digit character, and converting it back to an integer.
Replace all digits in the number with the largest digit found in step 3.
Add the encrypted number to the result.
Return the result.

Time Complexity:

The time complexity of this solution is O(n * m), where n is the number of elements in the input array and m is the maximum number of digits in any element.

Space Complexity:

The space complexity of this solution is O(1) as we are using only a constant amount of extra space.

Solution Code

class Solution {
    public int sumOfEncryptedIntegers(int[] nums) {
        int result = 0;
        for (int num : nums) {
            String numStr = String.valueOf(num);
            char maxDigit = Collections.max(numStr.chars().mapToObj(c -> (char) c).collect(Collectors.toList()));
            int encryptedNum = Integer.parseInt(String.valueOf(maxDigit).repeat(numStr.length()));
            result += encryptedNum;
        }
        return result;
    }
}

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