LeetCode 3085: Minimum Deletions to Make String K-Special Solution

Master LeetCode problem 3085 (Minimum Deletions to Make String K-Special), a medium challenge, with our optimized solutions in Java, C++, and Python. Explore detailed explanations, test your code in our interactive editor, and prepare for coding interviews.

3085. Minimum Deletions to Make String K-Special

Problem Explanation

Explanation:

To solve this problem, we can iterate through the string and calculate the frequency of each character. Then, we need to determine the minimum number of characters to delete to make the string k-special. We can achieve this by comparing the frequencies of different characters and keeping track of the minimum deletions required.

  1. Count the frequency of each character in the string.
  2. Iterate through the frequencies and check if the absolute difference between any two frequencies is greater than k. If it is, increment the deletions count.
  3. Return the total number of deletions needed.

Time Complexity: O(n), where n is the length of the input string word. Space Complexity: O(1) since the maximum size of the frequency array is constant (26 lowercase English letters).

:

Solution Code

class Solution {
    public int minDeletions(String word, int k) {
        int[] freq = new int[26]; // Assuming lowercase English letters
        for (char c : word.toCharArray()) {
            freq[c - 'a']++;
        }
        
        int deletions = 0;
        for (int i = 1; i < freq.length; i++) {
            if (freq[i] > 0) {
                int diff = Math.abs(freq[i] - freq[i - 1]);
                if (diff > k) {
                    deletions += diff - k;
                    freq[i] -= diff - k;
                }
            }
        }
        
        return deletions;
    }
}

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