LeetCode 3102: Minimize Manhattan Distances Solution

Master LeetCode problem 3102 (Minimize Manhattan Distances), a hard challenge, with our optimized solutions in Java, C++, and Python. Explore detailed explanations, test your code in our interactive editor, and prepare for coding interviews.

3102. Minimize Manhattan Distances

Problem Explanation

Explanation:

To solve this problem, we need to find the minimum possible value for the maximum distance between any two points by removing exactly one point. We can achieve this by iterating through each point, removing it, and calculating the maximum distance between the remaining points. The minimum of these maximum distances will be our answer.

  1. Create a helper function to calculate the Manhattan distance between two points.
  2. Iterate through each point and remove it from the array.
  3. For each iteration, calculate the maximum distance between the remaining points.
  4. Keep track of the minimum maximum distance found.
  5. Return the minimum maximum distance.

Time Complexity: O(n^2) where n is the number of points. Space Complexity: O(1) constant space is used.

Solution Code

class Solution {
    public int minMaxDistances(int[][] points) {
        int minMaxDistance = Integer.MAX_VALUE;
        
        for (int i = 0; i < points.length; i++) {
            int maxDistance = Integer.MIN_VALUE;
            for (int j = 0; j < points.length; j++) {
                if (i != j) {
                    maxDistance = Math.max(maxDistance, Math.abs(points[i][0] - points[j][0]) + Math.abs(points[i][1] - points[j][1]));
                }
            }
            minMaxDistance = Math.min(minMaxDistance, maxDistance);
        }
        
        return minMaxDistance;
    }
}

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