LeetCode 3103: Find Trending Hashtags II Solution
Master LeetCode problem 3103 (Find Trending Hashtags II ), a hard challenge, with our optimized solutions in Java, C++, and Python. Explore detailed explanations, test your code in our interactive editor, and prepare for coding interviews.
3103. Find Trending Hashtags II
Problem Explanation
Explanation:
To solve this problem, we can use a priority queue to keep track of the trending hashtags based on their frequency. We can iterate through the given list of hashtags and update the frequency of each hashtag in a hashmap. Then, we can add each hashtag to the priority queue based on its frequency. Finally, we can pop the top k hashtags from the priority queue to get the trending hashtags.
Algorithm:
- Initialize a hashmap to store the frequency of each hashtag.
- Iterate through the list of hashtags and update the frequency in the hashmap.
- Initialize a priority queue (max heap) to store the hashtags based on their frequency.
- Add each hashtag to the priority queue based on its frequency.
- Pop the top k hashtags from the priority queue to get the trending hashtags.
Time Complexity:
The time complexity of this approach is O(n log k), where n is the number of hashtags and k is the number of trending hashtags required.
Space Complexity:
The space complexity is O(n) to store the hashmap of hashtag frequencies and the priority queue.
:
Solution Code
import java.util.*;
class Solution {
public List<String> findTrendingHashtags(List<String> hashtags, int k) {
Map<String, Integer> freqMap = new HashMap<>();
for (String hashtag : hashtags) {
freqMap.put(hashtag, freqMap.getOrDefault(hashtag, 0) + 1);
}
PriorityQueue<String> pq = new PriorityQueue<>((a, b) -> freqMap.get(b) - freqMap.get(a));
pq.addAll(freqMap.keySet());
List<String> trending = new ArrayList<>();
for (int i = 0; i < k && !pq.isEmpty(); i++) {
trending.add(pq.poll());
}
return trending;
}
}Try It Yourself
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