LeetCode 3114: Latest Time You Can Obtain After Replacing Characters Solution

Master LeetCode problem 3114 (Latest Time You Can Obtain After Replacing Characters), a easy challenge, with our optimized solutions in Java, C++, and Python. Explore detailed explanations, test your code in our interactive editor, and prepare for coding interviews.

3114. Latest Time You Can Obtain After Replacing Characters

Easy

String Enumeration

Problem Explanation

Explanation:

To solve this problem, we need to replace the '?' characters in the input string with digits to obtain the latest valid 12-hour format time. We can do this by iterating through the string characters and replacing '?' based on specific conditions.

Here is the algorithm:

If the first digit is '?', we can replace it with '2' if the second digit is also '?' or less than '4'. Otherwise, we replace it with '1'.
For the second digit, if the first digit is '2' and the second digit is '?', we replace it with '3'. Otherwise, we replace it with '9'.
For the fourth digit (minutes tens place), we replace '?' with '5'.
For the fifth digit (minutes ones place), we replace '?' with '9'.

This way, we can obtain the latest valid 12-hour format time by replacing the '?' characters in the string.

Time complexity: O(1) as the input length is fixed.
Space complexity: O(1) as we are not using any additional data structures.

Solution Code

class Solution {
    public String maximumTime(String time) {
        char[] chars = time.toCharArray();
        
        if (chars[0] == '?') {
            chars[0] = (chars[1] == '?' || chars[1] <= '3') ? '2' : '1';
        }
        
        if (chars[1] == '?') {
            chars[1] = (chars[0] == '2') ? '3' : '9';
        }
        
        chars[3] = (chars[3] == '?') ? '5' : chars[3];
        chars[4] = (chars[4] == '?') ? '9' : chars[4];
        
        return new String(chars);
    }
}

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