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LeetCode 3131: Find the Integer Added to Array I Solution

Master LeetCode problem 3131 (Find the Integer Added to Array I), a easy challenge, with our optimized solutions in Java, C++, and Python. Explore detailed explanations, test your code in our interactive editor, and prepare for coding interviews.

3131. Find the Integer Added to Array I

Easy
Array

Problem Explanation

Explanation

To solve this problem, we need to find the integer x that has been added to each element of nums1 to transform it into nums2. We can do this by finding the difference between the sum of elements in nums2 and the sum of elements in nums1.

Algorithm

  1. Calculate the sum of elements in nums1 and nums2.
  2. Find the difference between the sum of elements in nums2 and the sum of elements in nums1.
  3. Return this difference as the integer x.

Time Complexity

The time complexity of this algorithm is O(n), where n is the length of the input arrays nums1 and nums2.

Space Complexity

The space complexity of this algorithm is O(1) as we are using only a constant amount of extra space.

Solution Code

class Solution {
    public int findIntegerAdded(int[] nums1, int[] nums2) {
        int sum1 = 0, sum2 = 0;
        for (int num : nums1) {
            sum1 += num;
        }
        for (int num : nums2) {
            sum2 += num;
        }
        return sum2 - sum1;
    }
}

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What is the time complexity of LeetCode 3131 (Find the Integer Added to Array I)?

The time complexity for LeetCode 3131 (Find the Integer Added to Array I) varies by solution. Check the detailed explanation section for specific complexities in Java, C++, and Python implementations.

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