LeetCode 3145: Find Products of Elements of Big Array Solution

Master LeetCode problem 3145 (Find Products of Elements of Big Array), a hard challenge, with our optimized solutions in Java, C++, and Python. Explore detailed explanations, test your code in our interactive editor, and prepare for coding interviews.

3145. Find Products of Elements of Big Array

Hard

Array Binary Search Bit Manipulation

Problem Explanation

Explanation:

To solve this problem, we need to first generate the powerful array for each integer i and then calculate the product of elements in the specified range [fromi, toi] and find the modulo with modi. We can optimize the calculation by precomputing the powerful arrays and storing them in a list. Then, for each query, we can directly retrieve the required elements from the precomputed list and calculate the product modulo the given mod.

Generate Powerful Arrays: Generate the powerful array for each integer i using the definition provided.
Precompute: Concatenate the powerful arrays for all integers i and store them in a list.
Process Queries: For each query, calculate the product of elements from the precomputed list within the specified range and find the modulo with the given mod.
Return Answer: Return the results for all queries in an integer array.

Time Complexity:

Generating powerful arrays: O(log x) for each number x
Precomputing: O(n log n) where n is the total number of elements in the concatenated powerful arrays
Processing queries: O(1) for each query Overall time complexity: O(n log n)

Space Complexity:

Storing precomputed powerful arrays: O(n)

Solution Code

class Solution {
    public int[] powerfulIntegers(int x, int y, int bound) {
        Set<Integer> powerfulIntegers = new HashSet<>();
        for (int i = 0; i < 20 && Math.pow(x, i) <= bound; i++) {
            for (int j = 0; j < 20 && Math.pow(y, j) <= bound; j++) {
                int val = (int) (Math.pow(x, i) + Math.pow(y, j));
                if (val <= bound) {
                    powerfulIntegers.add(val);
                }
                if (y == 1) break;
            }
            if (x == 1) break;
        }
        return powerfulIntegers.stream().mapToInt(Integer::intValue).toArray();
    }
}

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