LeetCode 3148: Maximum Difference Score in a Grid Solution
Master LeetCode problem 3148 (Maximum Difference Score in a Grid), a medium challenge, with our optimized solutions in Java, C++, and Python. Explore detailed explanations, test your code in our interactive editor, and prepare for coding interviews.
3148. Maximum Difference Score in a Grid
Problem Explanation
Explanation:
To solve this problem, we can iterate through the grid and calculate the maximum difference score we can achieve starting from each cell. We can maintain two 2D arrays, maxScore and minValue to store the maximum score achievable from each cell and the minimum value encountered on the path to that cell respectively.
We start by initializing maxScore and minValue arrays with appropriate values. Then, we iterate through the grid from top to bottom and left to right, updating the maxScore and minValue arrays accordingly. Finally, we return the maximum score achievable from any cell in the grid.
Time Complexity: O(mn) where m is the number of rows and n is the number of columns in the grid. Space Complexity: O(mn) for the two 2D arrays.
:
Solution Code
class Solution {
public int maxScore(int[][] grid) {
int m = grid.length;
int n = grid[0].length;
int[][] maxScore = new int[m][n];
int[][] minValue = new int[m][n];
for (int i = 0; i < m; i++) {
for (int j = 0; j < n; j++) {
maxScore[i][j] = Integer.MIN_VALUE;
minValue[i][j] = Integer.MAX_VALUE;
}
}
maxScore[0][0] = 0;
minValue[0][0] = grid[0][0];
for (int i = 0; i < m; i++) {
for (int j = 0; j < n; j++) {
if (i > 0) {
maxScore[i][j] = Math.max(maxScore[i][j], grid[i][j] - minValue[i - 1][j]);
minValue[i][j] = Math.min(minValue[i][j], Math.min(grid[i][j], minValue[i - 1][j]));
}
if (j > 0) {
maxScore[i][j] = Math.max(maxScore[i][j], grid[i][j] - minValue[i][j - 1]);
minValue[i][j] = Math.min(minValue[i][j], Math.min(grid[i][j], minValue[i][j - 1]));
}
}
}
return maxScore[m - 1][n - 1];
}
}Try It Yourself
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