LeetCode 3152: Special Array II Solution

Master LeetCode problem 3152 (Special Array II), a medium challenge, with our optimized solutions in Java, C++, and Python. Explore detailed explanations, test your code in our interactive editor, and prepare for coding interviews.

3152. Special Array II

Medium

Array Binary Search Prefix Sum

Problem Explanation

Explanation

To solve this problem, we need to check if each subarray specified by the queries is a special array. An array is special if every pair of adjacent elements contains two numbers with different parity. We can iterate through each query, check the parity of adjacent elements in the subarray, and determine if it is special or not.

Algorithm:
1. Iterate through each query.
2. For each query, iterate through the subarray specified by the query.
3. Check the parity of adjacent elements in the subarray.
4. If any pair of adjacent elements has the same parity, the subarray is not special.
5. Store the result for each query in the answer array.
Time Complexity: O(N + Q) where N is the length of the input array nums and Q is the number of queries.
Space Complexity: O(1)

Solution Code

class Solution {
    public List<Boolean> checkSpecialArray(int[] nums, int[][] queries) {
        List<Boolean> result = new ArrayList<>();
        for (int[] query : queries) {
            int from = query[0];
            int to = query[1];
            boolean isSpecial = true;
            for (int i = from; i < to; i++) {
                if (nums[i] % 2 == nums[i + 1] % 2) {
                    isSpecial = false;
                    break;
                }
            }
            result.add(isSpecial);
        }
        return result;
    }
}

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