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LeetCode 3153: Sum of Digit Differences of All Pairs Solution

Master LeetCode problem 3153 (Sum of Digit Differences of All Pairs), a medium challenge, with our optimized solutions in Java, C++, and Python. Explore detailed explanations, test your code in our interactive editor, and prepare for coding interviews.

3153. Sum of Digit Differences of All Pairs

Medium
ArrayHash TableMathCounting

Problem Explanation

Explanation

To solve this problem, we can iterate through all pairs of integers in the array nums, calculate the digit difference between each pair, and sum up these differences. The digit difference between two integers is the count of different digits that are in the same position in the two integers.

We can achieve this by iterating through each digit position in the integers, comparing the digits at the same position in the pair of integers, and incrementing the count of differences accordingly.

Algorithm:

  1. Initialize a variable totalDiff to store the total sum of digit differences.
  2. Iterate through all pairs of integers in nums.
  3. For each pair of integers, iterate through each digit position.
  4. Compare the digits at the same position in the pair of integers.
  5. If the digits are different, increment the totalDiff by 1.
  6. Return the totalDiff as the final result.

Time Complexity: O(n * m), where n is the number of integers in nums and m is the number of digits in each integer.
Space Complexity: O(1)

Solution Code

class Solution {
    public int totalDigitDifference(int[] nums) {
        int totalDiff = 0;
        for (int i = 0; i < nums.length; i++) {
            for (int j = i + 1; j < nums.length; j++) {
                totalDiff += getDigitDifference(nums[i], nums[j]);
            }
        }
        return totalDiff;
    }

    private int getDigitDifference(int num1, int num2) {
        int diff = 0;
        while (num1 > 0) {
            diff += (num1 % 10 != num2 % 10) ? 1 : 0;
            num1 /= 10;
            num2 /= 10;
        }
        return diff;
    }
}

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