LeetCode 3163: String Compression III Solution

Master LeetCode problem 3163 (String Compression III), a medium challenge, with our optimized solutions in Java, C++, and Python. Explore detailed explanations, test your code in our interactive editor, and prepare for coding interviews.

3163. String Compression III

Medium

String

Problem Explanation

Explanation:

We iterate over the input string word, keeping track of the current character and its count.
When we encounter a different character or reach the maximum count of 9 for the current character, we append the count and character to the result.
We continue this process until we reach the end of the string.

Time Complexity: O(n) where n is the length of the input string word Space Complexity: O(1)

Solution Code

class Solution {
    public String compress(String word) {
        StringBuilder sb = new StringBuilder();
        char prevChar = ' ';
        int count = 0;
        
        for (char c : word.toCharArray()) {
            if (c != prevChar || count == 9) {
                if (count > 0) {
                    sb.append(count);
                    sb.append(prevChar);
                }
                prevChar = c;
                count = 1;
            } else {
                count++;
            }
        }
        
        if (count > 0) {
            sb.append(count);
            sb.append(prevChar);
        }
        
        return sb.toString();
    }
}

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