LeetCode 3169: Count Days Without Meetings Solution

Master LeetCode problem 3169 (Count Days Without Meetings), a medium challenge, with our optimized solutions in Java, C++, and Python. Explore detailed explanations, test your code in our interactive editor, and prepare for coding interviews.

3169. Count Days Without Meetings

Medium

Array Sorting

Problem Explanation

Explanation:

To solve this problem, we can iterate through the meetings and mark the days when meetings are scheduled. Then, we can iterate through the total number of days and count the days when no meetings are scheduled.

Create a boolean array schedule of size days initialized with false.
Iterate through the meetings array and mark the days when meetings are scheduled in the schedule array.
Iterate through the total number of days and count the days when no meetings are scheduled.
Return the count of days without meetings.

Time Complexity: O(N), where N is the total number of days.

Space Complexity: O(N) for the boolean array schedule.

Solution Code

class Solution {
    public int countDaysWithoutMeetings(int days, int[][] meetings) {
        boolean[] schedule = new boolean[days + 1];
        for (int[] meeting : meetings) {
            for (int day = meeting[0]; day <= meeting[1]; day++) {
                schedule[day] = true;
            }
        }
        
        int count = 0;
        for (int day = 1; day <= days; day++) {
            if (!schedule[day]) {
                count++;
            }
        }
        
        return count;
    }
}

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