LeetCode 3171: Find Subarray With Bitwise OR Closest to K Solution

Master LeetCode problem 3171 (Find Subarray With Bitwise OR Closest to K), a hard challenge, with our optimized solutions in Java, C++, and Python. Explore detailed explanations, test your code in our interactive editor, and prepare for coding interviews.

3171. Find Subarray With Bitwise OR Closest to K

Hard

Array Binary Search Bit Manipulation Segment Tree

Problem Explanation

Explanation:

To solve this problem, we can iterate through all possible subarrays and calculate the bitwise OR value for each subarray. Then, we compare the absolute difference between the calculated OR value and the target value k to find the minimum absolute difference.

Here is the algorithm:

Initialize a variable minDiff to store the minimum absolute difference.
Iterate through all subarrays using two nested loops for start index i and end index j.
Calculate the bitwise OR value of the subarray elements between index i and j.
Update minDiff if the absolute difference between the calculated OR value and k is smaller than the current minDiff.
Return the final minDiff as the result.

Time Complexity: O(n^2) where n is the number of elements in the input array nums. Space Complexity: O(1)

Solution Code

class Solution {
    public int closestToTarget(int[] nums, int k) {
        int minDiff = Integer.MAX_VALUE;
        
        for (int i = 0; i < nums.length; i++) {
            int current = nums[i];
            minDiff = Math.min(minDiff, Math.abs(current - k));
            
            for (int j = i + 1; j < nums.length; j++) {
                current |= nums[j];
                minDiff = Math.min(minDiff, Math.abs(current - k));
                
                if (current == k) {
                    return 0;
                }
            }
        }
        
        return minDiff;
    }
}

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