LeetCode 3175: Find The First Player to win K Games in a Row Solution
Master LeetCode problem 3175 (Find The First Player to win K Games in a Row), a medium challenge, with our optimized solutions in Java, C++, and Python. Explore detailed explanations, test your code in our interactive editor, and prepare for coding interviews.
3175. Find The First Player to win K Games in a Row
Problem Explanation
Explanation
To find the first player to win k games in a row, we can simulate the competition process by using a queue to keep track of the players. We will iterate through the players, playing games until we find a player who wins k games in a row. We will track the current winning streak and reset it whenever a player loses. Once we find a player who wins k games in a row, we return their initial index.
Algorithm:
- Create a queue to store the indices of the players.
- Initialize variables for current winning streak and the player who won k games in a row.
- Iterate through the players:
- Compare the skill levels of the first two players in the queue.
- If the player with higher skill level wins, move them to the front of the queue and increment the winning streak.
- If the winning streak equals k, return the initial index of the winning player.
- Otherwise, move the losing player to the end of the queue and reset the winning streak.
- If no player wins k games in a row, return -1.
Time Complexity:
The time complexity of this algorithm is O(n), where n is the number of players.
Space Complexity:
The space complexity is O(n) to store the queue of players.
Solution Code
class Solution {
public int findTheWinner(int[] skills, int k) {
Queue<Integer> queue = new LinkedList<>();
for (int i = 0; i < skills.length; i++) {
queue.offer(i);
}
int winningStreak = 0;
int winner = -1;
while (!queue.isEmpty()) {
int player1 = queue.poll();
int player2 = queue.poll();
if (skills[player1] > skills[player2]) {
queue.offer(player1);
winningStreak++;
} else {
queue.offer(player2);
winningStreak = 1;
}
if (winningStreak == k) {
winner = queue.peek();
break;
}
}
return winner;
}
}Try It Yourself
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