LeetCode 3179: Find the N-th Value After K Seconds Solution

Master LeetCode problem 3179 (Find the N-th Value After K Seconds), a medium challenge, with our optimized solutions in Java, C++, and Python. Explore detailed explanations, test your code in our interactive editor, and prepare for coding interviews.

3179. Find the N-th Value After K Seconds

Problem Explanation

Explanation

To solve this problem, we can simulate the process described in the problem statement. We update the array a at each second by calculating the sum of all preceding elements plus the element itself. We repeat this process for k seconds and return the value of a[n-1] modulo 10^9 + 7.

Algorithm

  1. Initialize an array a of size n filled with 1s.
  2. Repeat the following steps k times:
    • Create a temporary array temp of size n.
    • Update each element of temp by summing all preceding elements plus the element itself from array a.
    • Copy the elements of temp back to array a.
  3. Return a[n-1] modulo 10^9 + 7 as the result.

Time Complexity

The time complexity of this approach is O(n*k) where n is the size of the array and k is the number of seconds.

Space Complexity

The space complexity of this approach is O(n) where n is the size of the array.

Solution Code

class Solution {
    public int findValue(int n, int k) {
        int MOD = 1000000007;
        int[] a = new int[n];
        Arrays.fill(a, 1);
        
        for (int i = 0; i < k; i++) {
            int[] temp = new int[n];
            for (int j = 0; j < n; j++) {
                for (int l = 0; l <= j; l++) {
                    temp[j] = (temp[j] + a[l]) % MOD;
                }
            }
            a = temp;
        }
        
        return a[n-1];
    }
}

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