LeetCode 3179: Find the N-th Value After K Seconds Solution
Master LeetCode problem 3179 (Find the N-th Value After K Seconds), a medium challenge, with our optimized solutions in Java, C++, and Python. Explore detailed explanations, test your code in our interactive editor, and prepare for coding interviews.
3179. Find the N-th Value After K Seconds
Problem Explanation
Explanation
To solve this problem, we can simulate the process described in the problem statement. We update the array a at each second by calculating the sum of all preceding elements plus the element itself. We repeat this process for k seconds and return the value of a[n-1] modulo 10^9 + 7.
Algorithm
- Initialize an array
aof sizenfilled with 1s. - Repeat the following steps
ktimes:- Create a temporary array
tempof sizen. - Update each element of
tempby summing all preceding elements plus the element itself from arraya. - Copy the elements of
tempback to arraya.
- Create a temporary array
- Return
a[n-1]modulo 10^9 + 7 as the result.
Time Complexity
The time complexity of this approach is O(n*k) where n is the size of the array and k is the number of seconds.
Space Complexity
The space complexity of this approach is O(n) where n is the size of the array.
Solution Code
class Solution {
public int findValue(int n, int k) {
int MOD = 1000000007;
int[] a = new int[n];
Arrays.fill(a, 1);
for (int i = 0; i < k; i++) {
int[] temp = new int[n];
for (int j = 0; j < n; j++) {
for (int l = 0; l <= j; l++) {
temp[j] = (temp[j] + a[l]) % MOD;
}
}
a = temp;
}
return a[n-1];
}
}Try It Yourself
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