LeetCode 3180: Maximum Total Reward Using Operations I Solution

Master LeetCode problem 3180 (Maximum Total Reward Using Operations I), a medium challenge, with our optimized solutions in Java, C++, and Python. Explore detailed explanations, test your code in our interactive editor, and prepare for coding interviews.

3180. Maximum Total Reward Using Operations I

Medium

Array Dynamic Programming

Problem Explanation

Explanation:

To maximize the total reward, we need to choose the indices with the maximum reward values while ensuring that we mark each index only if the reward value is greater than the current total reward. We can achieve this by iterating through the reward values and maintaining a running total of the rewards collected. If the current reward value is greater than the total reward, we update the total reward and mark the index.

Algorithm:

Initialize total reward x = 0 and a set to keep track of marked indices.
Iterate through the reward values:
- If the reward value at the current index is greater than x, add it to x and mark the index.
Return the final total reward x.

Time Complexity: O(n), where n is the number of elements in the rewardValues array. Space Complexity: O(n) for the set to store marked indices.

Solution Code

class Solution {
    public int maxTotalReward(int[] rewardValues) {
        int n = rewardValues.length;
        int totalReward = 0;
        Set<Integer> markedIndices = new HashSet<>();

        for (int i = 0; i < n; i++) {
            if (rewardValues[i] > totalReward) {
                totalReward += rewardValues[i];
                markedIndices.add(i);
            }
        }

        return totalReward;
    }
}

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