LeetCode 3183: The Number of Ways to Make the Sum Solution

Master LeetCode problem 3183 (The Number of Ways to Make the Sum), a medium challenge, with our optimized solutions in Java, C++, and Python. Explore detailed explanations, test your code in our interactive editor, and prepare for coding interviews.

3183. The Number of Ways to Make the Sum

Medium

Array Dynamic Programming

Problem Explanation

Explanation:

Given a list of integers nums and an integer target, we need to find the number of ways to make the sum of elements in nums equal to target. Each element in nums can be used multiple times.

To solve this problem, we can use dynamic programming. We will create a 1D array dp where dp[i] represents the number of ways to make the sum i using the elements in nums.

We initialize dp[0] = 1 because there is 1 way to make the sum 0 (by selecting no elements). Then, for each element num in nums, we update the dp array as follows:

For each index i from num to target, we update dp[i] += dp[i - num]. This means that we add the number of ways to make the sum i - num using the current element num.

Finally, the answer will be dp[target] which represents the number of ways to make the sum target.

: :

Solution Code

class Solution {
    public int numberOfWaysToMakeSum(int[] nums, int target) {
        int[] dp = new int[target + 1];
        dp[0] = 1;

        for (int num : nums) {
            for (int i = num; i <= target; i++) {
                dp[i] += dp[i - num];
            }
        }

        return dp[target];
    }
}

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