LeetCode 3191: Minimum Operations to Make Binary Array Elements Equal to One I Solution

Master LeetCode problem 3191 (Minimum Operations to Make Binary Array Elements Equal to One I), a medium challenge, with our optimized solutions in Java, C++, and Python. Explore detailed explanations, test your code in our interactive editor, and prepare for coding interviews.

3191. Minimum Operations to Make Binary Array Elements Equal to One I

Problem Explanation

Explanation:

To solve this problem, we need to find the minimum number of operations required to make all elements in the binary array nums equal to 1. We can achieve this by iterating through the array and checking whether each group of three consecutive elements contains at least one 0. If a group contains a 0, we perform the operation of flipping all three elements to 1. We keep track of the count of operations performed and return this count as the result. If it is impossible to make all elements equal to 1, we return -1.

Here are the steps:

  1. Iterate through the array in groups of three consecutive elements.
  2. For each group, check if there is at least one 0.
  3. If there is a 0, perform the operation of flipping all three elements to 1.
  4. Increment the count of operations performed.
  5. Continue until the end of the array or until it is impossible to make all elements equal to 1. Solution:

Solution Code

class Solution {
    public int minOperations(int[] nums) {
        int n = nums.length;
        int count = 0;
        
        for (int i = 0; i < n; i++) {
            if (i + 2 < n && nums[i] + nums[i + 1] + nums[i + 2] < 3) {
                nums[i] = nums[i + 1] = nums[i + 2] = 1;
                count++;
            } else if (i + 2 < n) {
                i += 2;
            }
        }
        
        for (int i = n - 1; i >= 0; i--) {
            if (nums[i] == 0) {
                return -1;
            }
        }
        
        return count;
    }
}

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