LeetCode 3194: Minimum Average of Smallest and Largest Elements Solution

Master LeetCode problem 3194 (Minimum Average of Smallest and Largest Elements), a easy challenge, with our optimized solutions in Java, C++, and Python. Explore detailed explanations, test your code in our interactive editor, and prepare for coding interviews.

3194. Minimum Average of Smallest and Largest Elements

Easy

Array Two Pointers Sorting

Problem Explanation

Explanation:

To solve this problem, we can use a greedy approach. We will sort the input array nums and then iterate through it in pairs, each time taking the minimum and maximum elements. We will calculate the average of these two elements and add it to the averages array. Finally, we return the minimum element in the averages array.

Sort the input array nums.
Initialize an empty array averages to store the averages.
Iterate through the sorted nums array in pairs, taking the minimum and maximum elements, calculating their average, and adding it to the averages array.
Return the minimum element in the averages array.

Time Complexity:

The time complexity of this approach is O(nlogn) due to the sorting step, where n is the number of elements in the input array nums.

Space Complexity:

The space complexity is O(n) to store the sorted array and the averages array.

Solution Code

import java.util.Arrays;

class Solution {
    public double minAverageOfSmallestAndLargest(int[] nums) {
        Arrays.sort(nums);
        double[] averages = new double[nums.length / 2];
        
        for (int i = 0; i < nums.length / 2; i++) {
            averages[i] = (nums[i] + nums[nums.length - 1 - i]) / 2.0;
        }
        
        Arrays.sort(averages);
        return averages[0];
    }
}

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