LeetCode 3200: Maximum Height of a Triangle Solution
Master LeetCode problem 3200 (Maximum Height of a Triangle), a easy challenge, with our optimized solutions in Java, C++, and Python. Explore detailed explanations, test your code in our interactive editor, and prepare for coding interviews.
3200. Maximum Height of a Triangle
Problem Explanation
Explanation:
To maximize the height of the triangle, we need to distribute the red and blue balls in a way that allows us to form the maximum number of rows. We can achieve this by distributing the balls in alternating colors in a way that maximizes the number of rows.
- Calculate the minimum number of balls required to form a complete row:
row = 1 + 2 + 3 + ... + n = n * (n + 1) / 2 - Start with the smaller count of balls (red or blue) and calculate the maximum possible height using the formula:
height = (int) (Math.sqrt(2 * totalBalls + 0.25) - 0.5) - Check if the calculated height is valid for both colors. If it is, return the minimum of the two heights as the result.
Time Complexity: O(1) Space Complexity: O(1)
:
Solution Code
class Solution {
public int maxHeight(int red, int blue) {
int totalBalls = red + blue;
int heightRed = (int) (Math.sqrt(2 * red + 0.25) - 0.5);
int heightBlue = (int) (Math.sqrt(2 * blue + 0.25) - 0.5);
return Math.min(heightRed, heightBlue);
}
}Try It Yourself
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