LeetCode 3205: Maximum Array Hopping Score I Solution

Master LeetCode problem 3205 (Maximum Array Hopping Score I), a medium challenge, with our optimized solutions in Java, C++, and Python. Explore detailed explanations, test your code in our interactive editor, and prepare for coding interviews.

3205. Maximum Array Hopping Score I

Medium

Array Dynamic Programming Stack Greedy Monotonic Stack

Problem Explanation

Explanation

This problem can be solved using dynamic programming. We can define an array dp where dp[i] represents the maximum hopping score that can be achieved starting at index i. We can fill this array in a bottom-up manner by considering the maximum score that can be achieved from each index by hopping to the next valid indices within the hopping range.

Algorithm

Initialize an array dp of size equal to the input array nums.
Start filling the dp array from the end.
For each index i, calculate the maximum score that can be achieved by hopping to the next valid indices within the hopping range.
Finally, the maximum hopping score will be the maximum value in the dp array.

Time Complexity

The time complexity of this solution is O(n) where n is the size of the input array.

Space Complexity

The space complexity of this solution is O(n) for the dp array.

Solution Code

class Solution {
    public int maxHoppingScore(int[] nums, int hopRange) {
        int n = nums.length;
        int[] dp = new int[n];
        dp[n-1] = nums[n-1];
        
        for (int i = n - 2; i >= 0; i--) {
            int maxScore = 0;
            for (int j = i + 1; j <= Math.min(n - 1, i + hopRange); j++) {
                maxScore = Math.max(maxScore, dp[j]);
            }
            dp[i] = nums[i] + maxScore;
        }
        
        return dp[0];
    }
}

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