LeetCode 3208: Alternating Groups II Solution

Master LeetCode problem 3208 (Alternating Groups II), a medium challenge, with our optimized solutions in Java, C++, and Python. Explore detailed explanations, test your code in our interactive editor, and prepare for coding interviews.

3208. Alternating Groups II

Medium

Array Sliding Window

Problem Explanation

Explanation:

To solve this problem, we can iterate through the circle of tiles and check each group of k contiguous tiles to see if they form an alternating group. If a group satisfies the alternating condition, we increment the count of alternating groups.

Algorithm:

Initialize a variable count to store the number of alternating groups.
Iterate through the circle of tiles using a loop from 0 to n-k.
For each index i, check if the next k tiles form an alternating group.
If the group is alternating, increment count.
Return the final value of count as the result.

Time Complexity: O(n) Space Complexity: O(1)

Solution Code

class Solution {
    public int countAlternatingGroups(int[] colors, int k) {
        int count = 0;
        for (int i = 0; i < colors.length; i++) {
            int sameColorCount = 0;
            for (int j = 1; j < k; j++) {
                if (colors[(i + j) % colors.length] == colors[(i + j - 1) % colors.length]) {
                    sameColorCount++;
                }
            }
            if (sameColorCount == 0 || sameColorCount == k - 1) {
                count++;
            }
        }
        return count;
    }
}

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