LeetCode 3215: Count Triplets with Even XOR Set Bits II Solution

Master LeetCode problem 3215 (Count Triplets with Even XOR Set Bits II), a medium challenge, with our optimized solutions in Java, C++, and Python. Explore detailed explanations, test your code in our interactive editor, and prepare for coding interviews.

3215. Count Triplets with Even XOR Set Bits II

Medium

Array Bit Manipulation

Problem Explanation

Explanation

To solve this problem, we can iterate through all possible triplets of numbers and check if the XOR of all three numbers is even. We will maintain a count of such triplets and return the total count at the end. Since the input array can have up to 3000 elements, the brute force approach of checking all triplets will be feasible.

Algorithm

Initialize a variable count to 0 to store the count of triplets with even XOR.
Iterate through all triplets of numbers using three nested loops.
For each triplet, calculate the XOR of all three numbers and check if it is even.
If the XOR is even, increment the count variable.
Return the final count at the end.

Time Complexity

The time complexity of this approach is O(n^3) where n is the number of elements in the input array.

Space Complexity

The space complexity of this approach is O(1) as we are not using any extra space apart from a constant amount of space for variables.

Solution Code

class Solution {
    public int countTriplets(int[] arr) {
        int count = 0;
        for (int i = 0; i < arr.length; i++) {
            for (int j = i + 1; j < arr.length; j++) {
                for (int k = j + 1; k < arr.length; k++) {
                    if ((arr[i] ^ arr[j] ^ arr[k]) % 2 == 0) {
                        count++;
                    }
                }
            }
        }
        return count;
    }
}

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