LeetCode 3219: Minimum Cost for Cutting Cake II Solution
Master LeetCode problem 3219 (Minimum Cost for Cutting Cake II), a hard challenge, with our optimized solutions in Java, C++, and Python. Explore detailed explanations, test your code in our interactive editor, and prepare for coding interviews.
Problem Explanation
Explanation
To solve this problem, we can first sort the horizontalCut and verticalCut arrays in ascending order. Then, we need to find the maximum cost of horizontal cuts and vertical cuts. The minimum cost to cut the cake into 1x1 pieces is the product of the maximum horizontal cut cost and the maximum vertical cut cost. We need to calculate the cost modulo 10^9 + 7 to avoid integer overflow.
Time Complexity: O(mlogm + nlogn) where m is the length of horizontalCut and n is the length of verticalCut. Space Complexity: O(1)
Solution Code
class Solution {
public int maxArea(int h, int w, int[] horizontalCuts, int[] verticalCuts) {
Arrays.sort(horizontalCuts);
Arrays.sort(verticalCuts);
long maxH = Math.max(horizontalCuts[0], h - horizontalCuts[horizontalCuts.length - 1]);
long maxV = Math.max(verticalCuts[0], w - verticalCuts[verticalCuts.length - 1]);
for (int i = 1; i < horizontalCuts.length; i++) {
maxH = Math.max(maxH, horizontalCuts[i] - horizontalCuts[i - 1]);
}
for (int i = 1; i < verticalCuts.length; i++) {
maxV = Math.max(maxV, verticalCuts[i] - verticalCuts[i - 1]);
}
return (int)((maxH * maxV) % 1000000007);
}
}Try It Yourself
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