LeetCode 3223: Minimum Length of String After Operations Solution

Master LeetCode problem 3223 (Minimum Length of String After Operations), a medium challenge, with our optimized solutions in Java, C++, and Python. Explore detailed explanations, test your code in our interactive editor, and prepare for coding interviews.

3223. Minimum Length of String After Operations

Problem Explanation

Explanation

To solve this problem, we need to simulate the process of removing characters according to the given rules. We can iterate through the string and keep track of the indices of the characters that have duplicates on both sides. We can then remove the characters at those indices to minimize the length of the final string.

  1. Iterate through the string and keep track of the indices of characters that have duplicates on both sides.
  2. Remove the characters at those indices to minimize the length of the final string.
  3. Repeat the above steps until there are no more characters that can be removed according to the rules.

Time Complexity: O(n) where n is the length of the input string s. Space Complexity: O(n) for storing the indices of characters.

Solution Code

class Solution {
    public int minimumLength(String s) {
        StringBuilder sb = new StringBuilder(s);
        boolean removed = true;

        while (removed) {
            int n = sb.length();
            removed = false;

            for (int i = 1; i < n - 1; i++) {
                if (sb.charAt(i - 1) == sb.charAt(i) || sb.charAt(i) == sb.charAt(i + 1)) {
                    sb.delete(i - 1, i + 2);
                    removed = true;
                    break;
                }
            }
        }
        return sb.length();
    }
}

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