LeetCode 3229: Minimum Operations to Make Array Equal to Target Solution

Master LeetCode problem 3229 (Minimum Operations to Make Array Equal to Target), a hard challenge, with our optimized solutions in Java, C++, and Python. Explore detailed explanations, test your code in our interactive editor, and prepare for coding interviews.

3229. Minimum Operations to Make Array Equal to Target

Hard

Array Dynamic Programming Stack Greedy Monotonic Stack

Problem Explanation

Explanation

To solve this problem, we can iterate through the arrays nums and target simultaneously. For each pair of elements, we calculate the difference between them and add the absolute difference to a sum variable. This sum represents the total number of operations required to make nums equal to target.

Algorithm

Initialize a variable operations to 0.
Iterate through the arrays nums and target simultaneously.
For each pair of elements nums[i] and target[i], calculate the absolute difference diff = abs(nums[i] - target[i] and add it to operations.
Return operations.

Time Complexity

The time complexity of this algorithm is O(n), where n is the length of the arrays nums and target.

Space Complexity

The space complexity is O(1) as we are using only a constant amount of extra space.

Solution Code

class Solution {
    public int minOperations(int[] nums, int[] target) {
        int operations = 0;
        for (int i = 0; i < nums.length; i++) {
            operations += Math.abs(nums[i] - target[i]);
        }
        return operations;
    }
}

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