LeetCode 3238: Find the Number of Winning Players Solution

Master LeetCode problem 3238 (Find the Number of Winning Players), a easy challenge, with our optimized solutions in Java, C++, and Python. Explore detailed explanations, test your code in our interactive editor, and prepare for coding interviews.

3238. Find the Number of Winning Players

Easy

Array Hash Table Counting

Problem Explanation

Explanation

To solve this problem, we can iterate through the pick array and keep track of the count of balls picked by each player. We can use a hashmap to store the count of balls picked by each player for each color. Then, for each player, we check if they have picked more balls of the same color than their player index. If so, we increment the count of winning players.

Algorithm:

Initialize a hashmap to store the count of balls picked by each player for each color.
Iterate through the pick array:
- Update the count of balls picked by the player for the specific color.
- Check if the player has picked more balls of the same color than their player index. If so, increment the count of winning players.
Return the count of winning players.

Time Complexity

The time complexity of this approach is O(n) where n is the number of elements in the pick array.

Space Complexity

The space complexity is O(n) to store the hashmap where n is the number of players.

Solution Code

class Solution {
    public int findTheNumberofWinningPlayers(int n, int[][] pick) {
        int[] wins = new int[n];
        Map<Integer, Map<Integer, Integer>> colorCounts = new HashMap<>();
        
        for (int i = 0; i < pick.length; i++) {
            int player = pick[i][0];
            int color = pick[i][1];
            
            colorCounts.putIfAbsent(player, new HashMap<>());
            colorCounts.get(player).put(color, colorCounts.get(player).getOrDefault(color, 0) + 1);
            
            if (colorCounts.get(player).get(color) > player) {
                wins[player]++;
            }
        }
        
        int count = 0;
        for (int win : wins) {
            if (win > 0) {
                count++;
            }
        }
        
        return count;
    }
}

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