LeetCode 324: Wiggle Sort II Solution
Master LeetCode problem 324 (Wiggle Sort II), a medium challenge, with our optimized solutions in Java, C++, and Python. Explore detailed explanations, test your code in our interactive editor, and prepare for coding interviews.
324. Wiggle Sort II
Problem Explanation
Explanation
To solve this problem, we will first sort the array in non-decreasing order. Then, we will rearrange the sorted array in a "wiggle" pattern by placing the larger elements in the odd indices and the smaller elements in the even indices.
- Sort the array.
- Create two pointers, one starting from the end of the smaller half and the other starting from the end of the array.
- Alternate between placing elements from the larger half and the smaller half into the odd and even indices of the result array.
Time complexity: O(n log n) for sorting the array, where n is the number of elements in the array.
Space complexity: O(n) for the sorted array.
Solution Code
import java.util.Arrays;
class Solution {
public void wiggleSort(int[] nums) {
int[] sorted = nums.clone();
Arrays.sort(sorted);
int n = nums.length;
int left = (n + 1) / 2 - 1;
int right = n - 1;
for (int i = 0; i < n; i++) {
nums[i] = (i % 2 == 0) ? sorted[left--] : sorted[right--];
}
}
}Try It Yourself
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