LeetCode 3242: Design Neighbor Sum Service Solution

Master LeetCode problem 3242 (Design Neighbor Sum Service), a easy challenge, with our optimized solutions in Java, C++, and Python. Explore detailed explanations, test your code in our interactive editor, and prepare for coding interviews.

3242. Design Neighbor Sum Service

Easy

Array Hash Table Design Matrix Simulation

Problem Explanation

Explanation

To solve this problem, we can create a NeighborSum class that stores the grid and provides methods to calculate the sum of adjacent neighbors and diagonal neighbors of a given value in the grid.

For each value, we can determine its adjacent and diagonal neighbors by checking the surrounding elements in the grid. We need to handle boundary cases to ensure we are not accessing elements outside the grid.

Algorithm:

Initialize the NeighborSum class with the given grid.
Implement the adjacentSum method:
- Calculate the row and column of the given value.
- Check the top, bottom, left, and right neighbors of the value and add them to the sum if they are within the grid boundaries.
Implement the diagonalSum method:
- Calculate the row and column of the given value.
- Check the diagonal neighbors (top-left, top-right, bottom-left, bottom-right) of the value and add them to the sum if they are within the grid boundaries.

Time Complexity:

The time complexity for both adjacentSum and diagonalSum methods is O(1) since we are checking a fixed number of neighbors.

Space Complexity:

The space complexity is O(1) as we are not using any extra space proportional to the input size.

Solution Code

class NeighborSum {
    private int[][] grid;

    public NeighborSum(int[][] grid) {
        this.grid = grid;
    }

    public int adjacentSum(int value) {
        int n = grid.length;
        int row = value / n;
        int col = value % n;

        int sum = 0;
        if (row > 0) sum += grid[row - 1][col]; // top neighbor
        if (row < n - 1) sum += grid[row + 1][col]; // bottom neighbor
        if (col > 0) sum += grid[row][col - 1]; // left neighbor
        if (col < n - 1) sum += grid[row][col + 1]; // right neighbor

        return sum;
    }

    public int diagonalSum(int value) {
        int n = grid.length;
        int row = value / n;
        int col = value % n;

        int sum = 0;
        if (row > 0 && col > 0) sum += grid[row - 1][col - 1]; // top-left neighbor
        if (row > 0 && col < n - 1) sum += grid[row - 1][col + 1]; // top-right neighbor
        if (row < n - 1 && col > 0) sum += grid[row + 1][col - 1]; // bottom-left neighbor
        if (row < n - 1 && col < n - 1) sum += grid[row + 1][col + 1]; // bottom-right neighbor

        return sum;
    }
}

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