LeetCode 3287: Find the Maximum Sequence Value of Array Solution
Master LeetCode problem 3287 (Find the Maximum Sequence Value of Array), a hard challenge, with our optimized solutions in Java, C++, and Python. Explore detailed explanations, test your code in our interactive editor, and prepare for coding interviews.
3287. Find the Maximum Sequence Value of Array
Problem Explanation
Explanation:
To solve this problem, we need to find the maximum value of the XOR operation within subsequences of size 2 * k in the given array. We can approach this problem by iterating through all possible subsequences of size 2 * k and calculating the XOR value for each subsequence. The maximum XOR value among all subsequences will be our answer.
Here is the algorithmic idea:
- Iterate through all possible subsequences of size 2 * k in the array.
- Calculate the XOR value for each subsequence.
- Keep track of the maximum XOR value found.
Time Complexity: The time complexity of this approach is O(n * 2^(2k)), where n is the length of the input array and k is the given parameter.
Space Complexity: The space complexity is O(1) as we are not using any extra space other than a few variables.
Solution Code
class Solution {
public int findMaximumXORValue(int[] nums, int k) {
int n = nums.length;
int max = 0;
for (int i = 0; i < (1 << n); i++) {
if (Integer.bitCount(i) == 2 * k) {
int seq = 0;
for (int j = 0; j < n; j++) {
if ((i & (1 << j)) != 0) {
seq ^= nums[j];
}
}
max = Math.max(max, seq);
}
}
return max;
}
}Try It Yourself
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