LeetCode 3289: The Two Sneaky Numbers of Digitville Solution
Master LeetCode problem 3289 (The Two Sneaky Numbers of Digitville), a easy challenge, with our optimized solutions in Java, C++, and Python. Explore detailed explanations, test your code in our interactive editor, and prepare for coding interviews.
3289. The Two Sneaky Numbers of Digitville
Problem Explanation
Explanation
To find the two sneaky numbers in the given list, we can use a HashSet to keep track of the numbers we have seen so far. As we iterate through the list, if we encounter a number that is already in the HashSet, that number is one of the sneaky numbers. At the end of the iteration, the two numbers remaining in the HashSet are the two sneaky numbers.
- Time complexity: O(n)
- Space complexity: O(n)
Solution Code
import java.util.*;
class Solution {
public int[] findSneakyNumbers(int[] nums) {
Set<Integer> seen = new HashSet<>();
int[] sneakyNumbers = new int[2];
for (int num : nums) {
if (seen.contains(num)) {
if (sneakyNumbers[0] == 0) {
sneakyNumbers[0] = num;
} else {
sneakyNumbers[1] = num;
break;
}
} else {
seen.add(num);
}
}
return sneakyNumbers;
}
}Try It Yourself
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