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LeetCode 3299: Sum of Consecutive Subsequences Solution

Master LeetCode problem 3299 (Sum of Consecutive Subsequences), a hard challenge, with our optimized solutions in Java, C++, and Python. Explore detailed explanations, test your code in our interactive editor, and prepare for coding interviews.

3299. Sum of Consecutive Subsequences

Hard
ArrayHash TableDynamic Programming

Problem Explanation

Explanation

To solve this problem, we need to find the sum of all consecutive subsequences in a given array. One way to approach this is by considering all possible pairs of indices (i, j) where 0 <= i < j < n. For each pair, we calculate the sum of elements between i and j and add it to the total sum.

Algorithmic Idea

  1. Initialize a variable totalSum to store the final result.
  2. Iterate over all possible pairs of indices (i, j) where 0 <= i < j < n.
  3. For each pair, calculate the sum of elements between i and j and add it to totalSum.
  4. Return totalSum as the result.

Time Complexity

The time complexity of this approach is O(n^2) where n is the length of the input array.

Space Complexity

The space complexity is O(1) as we are not using any extra space.

Solution Code

class Solution {
    public int sumOfConsecutiveSubsequences(int[] nums) {
        int totalSum = 0;
        int n = nums.length;
        
        for (int i = 0; i < n; i++) {
            for (int j = i + 1; j < n; j++) {
                int sum = 0;
                for (int k = i; k <= j; k++) {
                    sum += nums[k];
                }
                totalSum += sum;
            }
        }
        
        return totalSum;
    }
}

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