3300. Minimum Element After Replacement With Digit Sum
Explanation
To solve this problem, we iterate through each element in the array, calculate the sum of digits for each element, and replace the element with this sum. Finally, we find the minimum element in the modified array.
- Iterate through the array.
- For each element, calculate the sum of its digits.
- Replace the element with this sum.
- Find the minimum element in the modified array.
Time complexity: O(n * log(max(nums[i]))) where n is the number of elements in the array and log(max(nums[i])) represents the number of digits in the maximum number in the array. Space complexity: O(1)
class Solution {
public int findMin(int[] nums) {
for (int i = 0; i < nums.length; i++) {
int sum = 0;
int num = nums[i];
while (num > 0) {
sum += num % 10;
num /= 10;
}
nums[i] = sum;
}
int min = Integer.MAX_VALUE;
for (int num : nums) {
min = Math.min(min, num);
}
return min;
}
}Code Editor (Testing phase)
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