LeetCode 3308: Find Top Performing Driver Solution

Master LeetCode problem 3308 (Find Top Performing Driver), a medium challenge, with our optimized solutions in Java, C++, and Python. Explore detailed explanations, test your code in our interactive editor, and prepare for coding interviews.

3308. Find Top Performing Driver

Medium

Database

Problem Explanation

Explanation:

To find the top performing driver, we can iterate through the given list of drivers and calculate their performance score based on the given formula. We will keep track of the maximum performance score and the driver with the highest performance score. In case of ties, we will choose the driver with the lower index.

Algorithm:

Initialize variables maxScore as -1 and topDriver as -1 to store the maximum performance score and the top performing driver's index.
Iterate through the list of drivers.
Calculate the performance score for each driver using the given formula.
If the current driver's performance score is greater than maxScore, update maxScore and topDriver.
If the current driver's performance score is equal to maxScore, update topDriver only if the current driver has a lower index.
Return the topDriver as the top performing driver.

Time Complexity:

The time complexity of this solution is O(N), where N is the number of drivers in the input list.

Space Complexity:

The space complexity of this solution is O(1) as we are using constant extra space.: :

Solution Code

public int findTopPerformingDriver(int[] driverScores) {
    int maxScore = -1;
    int topDriver = -1;

    for (int i = 0; i < driverScores.length; i++) {
        int score = driverScores[i] * (i + 1);
        if (score > maxScore || (score == maxScore && i < topDriver)) {
            maxScore = score;
            topDriver = i;
        }
    }

    return topDriver;
}

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