LeetCode 334: Increasing Triplet Subsequence Solution

Master LeetCode problem 334 (Increasing Triplet Subsequence), a medium challenge, with our optimized solutions in Java, C++, and Python. Explore detailed explanations, test your code in our interactive editor, and prepare for coding interviews.

334. Increasing Triplet Subsequence

Medium

Array Greedy

Problem Explanation

Explanation:

To solve this problem in O(n) time complexity and O(1) space complexity, we can use a two-pointer approach. We maintain two variables, first and second, to keep track of the smallest and second smallest elements found so far. We iterate through the array and update these variables accordingly. If we encounter a number greater than both first and second, we have found a triplet and return true. If not, we keep updating first and second. If we finish iterating through the array without finding a triplet, we return false.

Time complexity: O(n) where n is the number of elements in the array.
Space complexity: O(1)

Solution Code

class Solution {
    public boolean increasingTriplet(int[] nums) {
        if(nums == null || nums.length < 3) {
            return false;
        }
        
        int first = Integer.MAX_VALUE;
        int second = Integer.MAX_VALUE;
        
        for(int num : nums) {
            if(num <= first) {
                first = num;
            } else if(num <= second) {
                second = num;
            } else {
                return true;
            }
        }
        
        return false;
    }
}

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