LeetCode 3346: Maximum Frequency of an Element After Performing Operations I Solution

Master LeetCode problem 3346 (Maximum Frequency of an Element After Performing Operations I), a medium challenge, with our optimized solutions in Java, C++, and Python. Explore detailed explanations, test your code in our interactive editor, and prepare for coding interviews.

3346. Maximum Frequency of an Element After Performing Operations I

Medium

Array Binary Search Sliding Window Sorting Prefix Sum

Problem Explanation

Explanation:

To solve this problem, we can simulate the process of performing the operations on the array nums. We will keep track of how many times each element appears in the array after each operation. We can do this by maintaining a map (or dictionary) where the keys are the elements in the array and the values are their frequencies.

For each operation, we will select an index i that has not been selected before, and add a random integer in the range [-k, k] to nums[i]. We then update the frequency of the modified element in our map. Finally, we find the maximum frequency of any element in the map after all operations are performed.

After each operation, we need to update the frequencies in the map and keep track of the maximum frequency achieved.

Solution Code

import java.util.*;

class Solution {
    public int maxFrequency(int[] nums, int k, int numOperations) {
        Map<Integer, Integer> freqMap = new HashMap<>();
        int maxFreq = 0;
        
        for (int i = 0; i < numOperations; i++) {
            int index = (int)(Math.random() * nums.length);
            int diff = (int)(Math.random() * (2 * k + 1)) - k;
            
            nums[index] += diff;
            freqMap.put(nums[index], freqMap.getOrDefault(nums[index], 0) + 1);
            maxFreq = Math.max(maxFreq, freqMap.get(nums[index]));
        }
        
        return maxFreq;
    }
}

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