LeetCode 3349: Adjacent Increasing Subarrays Detection I Solution

Master LeetCode problem 3349 (Adjacent Increasing Subarrays Detection I), a easy challenge, with our optimized solutions in Java, C++, and Python. Explore detailed explanations, test your code in our interactive editor, and prepare for coding interviews.

3349. Adjacent Increasing Subarrays Detection I

Easy

Array

Problem Explanation

Explanation:

To solve this problem, we can iterate through the array nums and check if two adjacent subarrays of length k are strictly increasing. We can do this by iterating through the array and checking if the elements at index a+k-1 and b+k-1 are greater than the elements at index a and b, respectively.

Algorithm:

Iterate through the array nums from index 0 to nums.length - 2*k.
For each index i, check if the subarrays nums[i..i+k-1] and nums[i+k..i+2k-1] are strictly increasing.
If both subarrays are strictly increasing, return true.
If no such pair of adjacent increasing subarrays is found, return false.

Time Complexity:

The time complexity of this algorithm is O(n), where n is the length of the input array nums.

Space Complexity:

The space complexity of this algorithm is O(1) as we are using constant extra space.

Solution Code

class Solution {
    public boolean canFindSubarrays(int[] nums, int k) {
        for (int i = 0; i <= nums.length - 2 * k; i++) {
            if (isIncreasing(nums, i, k) && isIncreasing(nums, i + k, k)) {
                return true;
            }
        }
        return false;
    }

    private boolean isIncreasing(int[] nums, int start, int k) {
        for (int i = start; i < start + k - 1; i++) {
            if (nums[i] >= nums[i + 1]) {
                return false;
            }
        }
        return true;
    }
}

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