LeetCode 3350: Adjacent Increasing Subarrays Detection II Solution
Master LeetCode problem 3350 (Adjacent Increasing Subarrays Detection II), a medium challenge, with our optimized solutions in Java, C++, and Python. Explore detailed explanations, test your code in our interactive editor, and prepare for coding interviews.
3350. Adjacent Increasing Subarrays Detection II
Problem Explanation
Explanation:
To solve this problem, we can iterate through the array and maintain two pointers left and right representing the starting indices of the two adjacent subarrays of length k. We will initialize left at index 0 and right at index 1. Then, we will move right to the right as long as the subarray [left, left+k-1] and [right, right+k-1] are strictly increasing. If they are not strictly increasing, we will update left to right and increment right to continue searching for the next adjacent increasing subarrays.
We will keep track of the maximum value of k found so far. Finally, we return this maximum value of k.
Time Complexity: O(n) Space Complexity: O(1)
:
Solution Code
class Solution {
public int maxK(int[] nums) {
int n = nums.length;
int left = 0, right = 1;
int maxK = 0;
while (right < n) {
if (nums[right] > nums[right - 1]) {
maxK = Math.max(maxK, right - left + 1);
right++;
} else {
left = right;
right++;
}
}
return maxK;
}
}Try It Yourself
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