LeetCode 3352: Count K-Reducible Numbers Less Than N Solution

Master LeetCode problem 3352 (Count K-Reducible Numbers Less Than N), a hard challenge, with our optimized solutions in Java, C++, and Python. Explore detailed explanations, test your code in our interactive editor, and prepare for coding interviews.

3352. Count K-Reducible Numbers Less Than N

Hard

Math String Dynamic Programming Combinatorics

Problem Explanation

Explanation:

To solve this problem, we can iterate through all positive integers less than n, convert each integer to its binary representation, and then check if it is k-reducible by applying the reduction operation at most k times. We can use a helper function to count the set bits in a binary representation. Finally, we return the count of k-reducible numbers modulo 10^9 + 7.

Convert n to its binary representation.
Iterate through all positive integers less than n.
For each integer, apply the reduction operation at most k times.
Check if the resulting number is equal to 1 after applying the reduction operation.
Count the number of k-reducible integers.
Return the count modulo 10^9 + 7.

Time Complexity: O(n * k * log(n)) Space Complexity: O(log(n))

Solution Code

class Solution {
    public int countKReducibleNumbersLessThanN(String s, int k) {
        long n = Long.parseLong(s, 2);
        int count = 0;
        for (int i = 1; i < n; i++) {
            long num = i;
            for (int j = 0; j < k; j++) {
                int setBits = Integer.bitCount((int) num);
                if (setBits == 1) {
                    count++;
                    break;
                }
                num = setBits;
            }
        }
        return count % 1000000007;
    }
}

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