LeetCode 3354: Make Array Elements Equal to Zero Solution

Master LeetCode problem 3354 (Make Array Elements Equal to Zero), a easy challenge, with our optimized solutions in Java, C++, and Python. Explore detailed explanations, test your code in our interactive editor, and prepare for coding interviews.

3354. Make Array Elements Equal to Zero

Easy

Array Simulation Prefix Sum

Problem Explanation

Explanation:

To solve this problem, we can simulate the process described in the problem statement. We iterate through the array and whenever we encounter a zero, we can consider two cases:

Moving left: Decrement the elements to the left until they become zero, then move to the next zero element.
Moving right: Decrement the elements to the right until they become zero, then move to the next zero element.

We can try both cases recursively and count the number of valid selections where all elements become zero.

Algorithm:

Initialize a variable count to store the number of valid selections.
Iterate through the array nums.
Whenever a zero is encountered at position curr, simulate both movements (left and right) recursively.
If the simulation reaches the end of the array and all elements are zero, increment the count.
Return the final count as the result.

Time Complexity:

The time complexity of this approach is O(2^N) where N is the number of elements in the array.

Space Complexity:

The space complexity is O(N) for the recursive calls.

Solution Code

class Solution {
    public int makeEqual(int[] nums) {
        return countValidSelections(nums, 0);
    }

    private int countValidSelections(int[] nums, int curr) {
        if (curr == nums.length) {
            for (int num : nums) {
                if (num != 0) {
                    return 0;
                }
            }
            return 1;
        }

        int count = 0;
        if (nums[curr] == 0) {
            int[] numsLeft = nums.clone();
            int[] numsRight = nums.clone();

            for (int i = curr - 1; i >= 0 && numsLeft[i] > 0; i--) {
                numsLeft[i]--;
                count += countValidSelections(numsLeft, curr + 1);
            }

            for (int i = curr + 1; i < nums.length && numsRight[i] > 0; i++) {
                numsRight[i]--;
                count += countValidSelections(numsRight, curr + 1);
            }
        }

        return count;
    }
}

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