LeetCode 3379: Transformed Array Solution

Master LeetCode problem 3379 (Transformed Array), a easy challenge, with our optimized solutions in Java, C++, and Python. Explore detailed explanations, test your code in our interactive editor, and prepare for coding interviews.

3379. Transformed Array

Easy

Array Simulation

Problem Explanation

Explanation

To solve this problem, we iterate through the given nums array and perform the actions as described in the problem statement. We need to handle the cases where we move to the right, move to the left, or stay in place based on the value at each index in nums. We will be using modular arithmetic to handle circular array indexing.

If nums[i] > 0, we move nums[i] steps to the right in the circular array.
If nums[i] < 0, we move abs(nums[i]) steps to the left in the circular array.
If nums[i] == 0, we stay at the same index.

After determining the new index based on the above rules, we update the corresponding index in the result array.

Solution Code

class Solution {
    public int[] transformArray(int[] nums) {
        int n = nums.length;
        int[] result = new int[n];
        
        for (int i = 0; i < n; i++) {
            if (nums[i] > 0) {
                result[i] = (i + nums[i]) % n;
            } else if (nums[i] < 0) {
                result[i] = (i + nums[i] % n + n) % n;
            } else {
                result[i] = nums[i];
            }
        }
        
        return result;
    }
}

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