LeetCode 3392: Count Subarrays of Length Three With a Condition Solution

Master LeetCode problem 3392 (Count Subarrays of Length Three With a Condition), a easy challenge, with our optimized solutions in Java, C++, and Python. Explore detailed explanations, test your code in our interactive editor, and prepare for coding interviews.

3392. Count Subarrays of Length Three With a Condition

Easy

Problem Explanation

Explanation:

To solve this problem, we can iterate through the array and for each subarray of length 3, check if the sum of the first and third elements is equal to half of the second element. We can do this by iterating through the array and checking the conditions for each subarray of length 3.

Algorithm:

  1. Initialize a variable count to keep track of the number of valid subarrays.
  2. Iterate through the array from index 1 to nums.length - 2.
  3. For each index i, check if the sum of nums[i-1] and nums[i+1] is equal to half of nums[i].
  4. If the condition is met, increment count.
  5. Return the final value of count.

Time Complexity:

The time complexity of this solution is O(n), where n is the size of the input array nums.

Space Complexity:

The space complexity of this solution is O(1) as we are using only a constant amount of extra space.

Solution Code

class Solution {
    public int countSubarrays(int[] nums) {
        int count = 0;
        for (int i = 1; i < nums.length - 1; i++) {
            if (nums[i-1] + nums[i+1] == nums[i] / 2) {
                count++;
            }
        }
        return count;
    }
}

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