LeetCode 3399: Smallest Substring With Identical Characters II Solution

Master LeetCode problem 3399 (Smallest Substring With Identical Characters II), a hard challenge, with our optimized solutions in Java, C++, and Python. Explore detailed explanations, test your code in our interactive editor, and prepare for coding interviews.

3399. Smallest Substring With Identical Characters II

Hard

String Binary Search

Problem Explanation

Explanation

To solve this problem, we can use a sliding window approach. We will maintain a window that contains at most numOps zeros. We will expand the window until the number of zeros in the window is more than numOps. At each step, we will update the answer with the maximum window size.

Here are the detailed steps:

Initialize variables: start = 0, maxLen = 0, zeroCount = 0.
Iterate over the string using a pointer i:
- If s[i] is '0', increment zeroCount.
- If zeroCount > numOps, move the start pointer forward until zeroCount becomes less than or equal to numOps.
- Update maxLen with the maximum of current maxLen and (i - start + 1).
Return maxLen.

Time Complexity

The time complexity of this algorithm is O(n) where n is the length of the input string s.

Space Complexity

The space complexity is O(1) as we are using a constant amount of extra space.

Solution Code

class Solution {
    public int minOperations(String s, int numOps) {
        int start = 0, maxLen = 0, zeroCount = 0;
        
        for (int i = 0; i < s.length(); i++) {
            if (s.charAt(i) == '0') {
                zeroCount++;
            }
            
            while (zeroCount > numOps) {
                if (s.charAt(start) == '0') {
                    zeroCount--;
                }
                start++;
            }
            
            maxLen = Math.max(maxLen, i - start + 1);
        }
        
        return maxLen;
    }
}

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