LeetCode 3407: Substring Matching Pattern Solution
Master LeetCode problem 3407 (Substring Matching Pattern), a easy challenge, with our optimized solutions in Java, C++, and Python. Explore detailed explanations, test your code in our interactive editor, and prepare for coding interviews.
3407. Substring Matching Pattern
Problem Explanation
Explanation
To solve this problem, we can iterate through all possible positions where the '' character in the pattern string can be placed in the original string. We will try to match the pattern by replacing the '' character with different lengths of substrings from the original string. If at any point we find a match, we return true.
Algorithm:
- Iterate through all possible positions i in the original string where the '*' character can be placed.
- Try to match the pattern by replacing the '*' character with substrings of different lengths starting from position i in the original string.
- If the pattern matches at any point, return true.
- If no match is found, return false.
Time Complexity:
The time complexity of this algorithm is O(n*m), where n is the length of the original string and m is the length of the pattern string.
Space Complexity:
The space complexity of this algorithm is O(1), as we are not using any extra space proportional to the input size.
Solution Code
class Solution {
public boolean isMatch(String s, String p) {
for (int i = 0; i <= s.length() - p.length(); i++) {
boolean match = true;
for (int j = 0; j < p.length(); j++) {
if (p.charAt(j) != '*' && (i + j >= s.length() || s.charAt(i + j) != p.charAt(j))) {
match = false;
break;
}
}
if (match) return true;
}
return false;
}
}Try It Yourself
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