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LeetCode 3410: Maximize Subarray Sum After Removing All Occurrences of One Element Solution

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3410. Maximize Subarray Sum After Removing All Occurrences of One Element

Hard
ArrayDynamic ProgrammingSegment Tree

Problem Explanation

Explanation:

To solve this problem, we need to find the maximum subarray sum across all possible resulting arrays after removing all occurrences of one element. We can approach this problem by considering each unique element in the array as the element to be removed and calculating the maximum subarray sum for each case.

  1. Initialize variables to keep track of the overall maximum subarray sum, the current subarray sum, and the maximum sum ending at the current index.
  2. Iterate over each unique element in the array.
  3. For each unique element:
    • Remove all occurrences of that element from the array.
    • Use Kadane's algorithm to find the maximum subarray sum for the modified array.
    • Update the overall maximum subarray sum if the current sum is greater.
  4. Return the overall maximum subarray sum as the result.

:

Solution Code

class Solution {
    public int maximumSum(int[] nums) {
        int n = nums.length;
        int result = nums[0];
        
        for (int i = 0; i < n; i++) {
            int sum1 = 0, sum2 = 0, maxSum = Integer.MIN_VALUE;
            for (int j = 0; j < n; j++) {
                if (j == i) continue;
                sum2 = Math.max(sum2 + nums[j], sum1);
                sum1 = Math.max(sum1 + nums[j], nums[j]);
                maxSum = Math.max(maxSum, Math.max(sum1, sum2));
            }
            result = Math.max(result, maxSum);
        }
        
        return result;
    }
}

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