LeetCode 3413: Maximum Coins From K Consecutive Bags Solution

Master LeetCode problem 3413 (Maximum Coins From K Consecutive Bags), a medium challenge, with our optimized solutions in Java, C++, and Python. Explore detailed explanations, test your code in our interactive editor, and prepare for coding interviews.

3413. Maximum Coins From K Consecutive Bags

Medium

Array Binary Search Greedy Sliding Window Sorting Prefix Sum

Problem Explanation

Explanation:

To solve this problem, we can iterate through each bag and calculate the total coins that can be obtained by considering k consecutive bags starting at that bag. We can maintain a prefix sum array to efficiently calculate the total coins in any range of bags.

Initialize a prefix sum array to store the total coins up to each bag.
Iterate through each bag and update the prefix sum array.
For each bag, calculate the total coins in the range of k consecutive bags starting at that bag using the prefix sum array.
Keep track of the maximum total coins obtained.

Time Complexity:

We iterate through all bags once to calculate the prefix sum array which takes O(n) time.
Then, for each bag, we calculate the total coins in the range of k bags in O(1) time using the prefix sum array.
Thus, the total time complexity is O(n) where n is the number of bags.

Space Complexity:

We use O(n) extra space to store the prefix sum array.

Solution Code

class Solution {
    public int maxCoins(int[][] coins, int k) {
        int n = coins.length;
        int[] prefixSum = new int[n];
        for (int i = 0; i < n; i++) {
            prefixSum[i] = coins[i][2];
            if (i > 0) {
                prefixSum[i] += prefixSum[i - 1];
            }
        }
        
        int maxCoins = 0;
        for (int i = 0; i < n; i++) {
            int end = i + k - 1;
            if (end >= n) {
                break;
            }
            int currCoins = prefixSum[end] - (i > 0 ? prefixSum[i - 1] : 0);
            maxCoins = Math.max(maxCoins, currCoins);
        }
        
        return maxCoins;
    }
}

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