LeetCode 3415: Find Products with Three Consecutive Digits Solution

Master LeetCode problem 3415 (Find Products with Three Consecutive Digits ), a easy challenge, with our optimized solutions in Java, C++, and Python. Explore detailed explanations, test your code in our interactive editor, and prepare for coding interviews.

3415. Find Products with Three Consecutive Digits

Easy

Database

Problem Explanation

Explanation:

To solve this problem, we need to find all products that are generated by three consecutive digits. We can iterate through all three-digit numbers and check if they satisfy the condition of being consecutive digits. If a number satisfies the condition, we calculate its product and add it to the result list.

Algorithmic Steps:

Iterate through all three-digit numbers from 100 to 999.
Check if the digits are consecutive (e.g., 123, 234, 345, ...).
If the digits are consecutive, calculate the product and add it to the result list.
Return the list of products.

Time Complexity: O(900) = O(1) as we are iterating through a fixed range of three-digit numbers. Space Complexity: O(1) as we are not using any extra space other than the result list.

Solution Code

import java.util.ArrayList;
import java.util.List;

class Solution {
    public List<Integer> findProducts() {
        List<Integer> result = new ArrayList<>();
        for (int i = 100; i <= 999; i++) {
            int num = i;
            int digit1 = num % 10;
            num /= 10;
            int digit2 = num % 10;
            num /= 10;
            int digit3 = num % 10;
            if (digit2 - digit1 == 1 && digit3 - digit2 == 1) {
                result.add(digit1 * digit2 * digit3);
            }
        }
        return result;
    }
}

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